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A stretched string fixed at both ends has ‘m’ nodes, then the length of the string will be
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The correct answer is:
For p number of loops in stretched string, the length is given by
… (i)
As, number of harmonics = number of loops = number of anti-nodes = p …. (ii)
Also, number of nodes = number of anti-nodes + 1
Here, number of nodes = m
Number of anti-nodes = m-1 from Eq. (ii)
Putting this value of p in Eq. (i), we get
… (i)
As, number of harmonics = number of loops = number of anti-nodes = p …. (ii)
Also, number of nodes = number of anti-nodes + 1
Here, number of nodes = m
Number of anti-nodes = m-1 from Eq. (ii)
Putting this value of p in Eq. (i), we get
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