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Question: Answered & Verified by Expert
A string is wrapped around the rim of a wheel of moment of inertia $0.20 \mathrm{~kg}-\mathrm{m}^2$ and radius $20 \mathrm{~cm}$. The wheel is free to rotate about its axis initially the wheel is rest. The string is now pulled by a force of $20 \mathrm{~N}$. The angular velocity of the string after 5 seconds will be :

PhysicsRotational MotionJEE Main
Options:
  • A $70 \mathrm{rad} / \mathrm{s}$
  • B $90 \mathrm{rad} / \mathrm{s}$
  • C $95 \mathrm{rad} / \mathrm{s}$
  • D $100 \mathrm{rad} / \mathrm{s}$
Solution:
2368 Upvotes Verified Answer
The correct answer is: $100 \mathrm{rad} / \mathrm{s}$
Angular impulse $=$ change in angular momentum $\tau \mathbf{t}=\mathbf{I} \omega-0$


$\omega=\mathrm{F} \frac{\mathrm{Rt}}{\mathrm{I}}=\frac{20 \times 0.2}{0.2}=100 \mathrm{rad} / \mathrm{sec}$

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