A string of length 1 . 5 m with its two ends clamped is vibrating in the fundamental mode. The amplitude at the centre of the string is 4 mm . The minimum distance between the two points having amplitude of 2 mm is:

Question

A string of length 1 . 5 m with its two ends clamped is vibrating in the fundamental mode. The amplitude at the centre of the string is 4 mm . The minimum distance between the two points having amplitude of 2 mm is:, 1 m, 75 m, 60 m, 50 m

MARKS App · Accepted Answer

λ = 2 l = 3 m Equation of standing wave y = 2 A sin ⁡ k x cos ⁡ ω t y = A as amplitude is 2A. A = 2 A sin ⁡ k x 2 π λ x 1 = π 6 ⇒ x 1 = 1 4 m And 2 π λ . x 2 = 5 π 6 ⇒ x 2 = 1.25 m ⇒ x 2 - x 1 = 1 m

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