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Question: Answered & Verified by Expert
A string of length 1 m and mass 5 g is fixed at both ends. The tension in the string is 8.0 N. The string is set into vibration using an external vibrator of frequency 100 Hz. The separation between successive nodes on the string is close to
PhysicsWaves and SoundJEE MainJEE Main 2019 (10 Jan Shift 1)
Options:
  • A 20.0 cm
  • B 10.0 cm
  • C 16.6 cm
  • D 33.3 cm
Solution:
2087 Upvotes Verified Answer
The correct answer is: 20.0 cm
V=fλ

Tμ=fλ

85×10-3=100λ

λ=40cm

λ2=20 cm

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