Search any question & find its solution
Question:
Answered & Verified by Expert
A string of length $2 \mathrm{~m}$ is fixed at both ends. If this string vibrates in its fourth normal mode with a frequency of $500 \mathrm{~Hz}$ then the waves would travel on it's with a velocity of
Options:
Solution:
2666 Upvotes
Verified Answer
The correct answer is:
$500 \mathrm{~m} / \mathrm{s}$
$\begin{aligned} & \qquad \lambda=\frac{2 l}{p} \\ & \text { For string } \\ & \text { where } p=\text { No. of loops = Order of vibration } \\ & \text { Hence for forth mode } p=4 \Rightarrow \lambda=\frac{1}{2} \\ & \text { Hence } v=n \lambda \\ & \qquad 500 \times \frac{2}{2}=500 \mathrm{~Hz}\end{aligned}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.