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A string of length ' $L$ ' fixed at one end carries a body of mass ' $m$ ' at the other end. The mass is revolved in a circle in the horizontal plane about a vertical axis passing through the fixed end of the string. The string makes angle ' $\theta$ ' with the vertical. The angular frequency of the body is ' $\omega$ '. The tension in the string is
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The correct answer is:
$\mathrm{mL} \omega^2$
In case of conical pendulum, the tension in the string provides the necessary centripetal force.
$\therefore \quad \mathrm{T}=\mathrm{mr} \omega^2=\mathrm{mL} \omega^2 \quad \ldots($ Here, $\mathrm{r}=\mathrm{L})$
$\therefore \quad \mathrm{T}=\mathrm{mr} \omega^2=\mathrm{mL} \omega^2 \quad \ldots($ Here, $\mathrm{r}=\mathrm{L})$
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