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A string of mass $0 \cdot 1 \mathrm{~kg}$ is under a tension $1 \cdot 6 \mathrm{~N}$. The length of the string is $1 \mathrm{~m}$. A
transverse wave starts from one end of the string. The time taken by the wave to
reach the other end is
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transverse wave starts from one end of the string. The time taken by the wave to
reach the other end is
Solution:
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Verified Answer
The correct answer is:
$0.25 \mathrm{~s}$
Mass of string $=0.1 \mathrm{lgg}$
Tension $T=1.6 \mathrm{~N}$
Length $\quad \ell=1 \mathrm{~m}$
Man per unit length $\mu=\frac{m}{1}=\frac{0.1}{1}=0.1 \mathrm{~kg} / \mathrm{m}$
The velocity $(v)$ of the transverse wave in the string is given by the relation
$\begin{aligned}
V &=\sqrt{\frac{T}{4}} \\
&=\sqrt{\frac{1.6}{0.1}} \\
&=4 \mathrm{~m} / \mathrm{s}
\end{aligned}$
Time taken $T=\ell / V=1 / 4=0.25 \sec$
Tension $T=1.6 \mathrm{~N}$
Length $\quad \ell=1 \mathrm{~m}$
Man per unit length $\mu=\frac{m}{1}=\frac{0.1}{1}=0.1 \mathrm{~kg} / \mathrm{m}$
The velocity $(v)$ of the transverse wave in the string is given by the relation
$\begin{aligned}
V &=\sqrt{\frac{T}{4}} \\
&=\sqrt{\frac{1.6}{0.1}} \\
&=4 \mathrm{~m} / \mathrm{s}
\end{aligned}$
Time taken $T=\ell / V=1 / 4=0.25 \sec$
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