Search any question & find its solution
Question:
Answered & Verified by Expert
A string of mass $2.50 \mathrm{~kg}$ is under a tension of $200 \mathrm{~N}$. The length of the stretched string is $20 \mathrm{~m}$. If the transverse jerk is struck at one end of the string, how long does the disturbance take to reach the other end?
Solution:
2652 Upvotes
Verified Answer
Given, $M=2.5 \mathrm{~kg}, T=200 \mathrm{~N}, l=20 \mathrm{~m}$;
Mass/unit
Length, $m=\frac{M}{l}=\frac{2.5}{20}=0.125 \mathrm{~kg} / \mathrm{m}$
Velocity, $v=\sqrt{\frac{T}{m}}=\sqrt{\frac{200}{0.125}}=40 \mathrm{~m} / \mathrm{s}$
Time taken by disturbance to reach the other end,
$$
t=\frac{l}{v}=\frac{20}{40}=0.5 \mathrm{~s}
$$
Mass/unit
Length, $m=\frac{M}{l}=\frac{2.5}{20}=0.125 \mathrm{~kg} / \mathrm{m}$
Velocity, $v=\sqrt{\frac{T}{m}}=\sqrt{\frac{200}{0.125}}=40 \mathrm{~m} / \mathrm{s}$
Time taken by disturbance to reach the other end,
$$
t=\frac{l}{v}=\frac{20}{40}=0.5 \mathrm{~s}
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.