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Question: Answered & Verified by Expert
A string of mass per unit length μ is clamped at both ends such that one end of the string is at x = 0 and the other is at x = L. When the string vibrates in fundamental mode, the amplitude of the mid-point O of the string is a, and tension in the string is T, Find the total oscillation energy stored in the string.
PhysicsWaves and SoundJEE Main
Options:
  • A π 2 a 2 T 4 L
  • B π a T 2 L
  • C - π 2 a 2 T 3 L
  • D π 2 a T 6 L
Solution:
1386 Upvotes Verified Answer
The correct answer is: π 2 a 2 T 4 L
λ2=L

λ=2L

τ=μV2

The amplitude at a distance x from the origin is given by
A = asinkx
consider an element of mass dm and length dx of string at a distance x from the origin
The total energy of this element = its maximum KE

= 1 2 d m ω 2 A 2

= 1 2 μ d x 4 π 2 f 2 a 2 sin 2 k x

(Because μ= dm dx and  ω=2πf  and it is given that   A = a sinkx   )

total energy of string = 0 L 2 π 2 μ f 2 a 2 sin 2 k x d x

= π 2 μ f 2 a 2 [ x - sin 2 k x 2 ] 0 L

= π 2 μ f 2 a 2 L

= π 2 μ V 2 λ 2 a 2 L = π 2 4 L 2 T a 2 L = π 2 a 2 T 4 L

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