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A student made the following observations in the laboratory.
I. Clean copper metal did not react with 1 molar $\mathrm{Pb}\left(\mathrm{NO}_3\right)_2$ solution
II. Clean lead metal dissolved in a 1 molar $\mathrm{AgNO}_3$ solution and crystals of Ag metal appeared
III. Clean silver metal did not react with 1 molar $\mathrm{Cu}\left(\mathrm{NO}_3\right)_2$ solution
The order of decrease in reducing character of three metals is
Options:
I. Clean copper metal did not react with 1 molar $\mathrm{Pb}\left(\mathrm{NO}_3\right)_2$ solution
II. Clean lead metal dissolved in a 1 molar $\mathrm{AgNO}_3$ solution and crystals of Ag metal appeared
III. Clean silver metal did not react with 1 molar $\mathrm{Cu}\left(\mathrm{NO}_3\right)_2$ solution
The order of decrease in reducing character of three metals is
Solution:
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Verified Answer
The correct answer is:
$\mathrm{Pb}, \mathrm{Cu}, \mathrm{Ag}$
Metal placed above in electrochemical series replaces the other from its salt solution which is lower in the series.
The low $E^{\circ}$ value containing metals have the high reducing character.
Thus, order of reducing character of three metals is
$\mathrm{Pb}\gt\mathrm{Cu}\gt\mathrm{Ag}$
The low $E^{\circ}$ value containing metals have the high reducing character.
Thus, order of reducing character of three metals is
$\mathrm{Pb}\gt\mathrm{Cu}\gt\mathrm{Ag}$
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