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A student measures the terminal potential difference (V) of a cell (of emf $\varepsilon$ and internal) resistance $r$ ) as a function of the current (I) flowing through it. The slope and intercept of the graph between $\mathrm{V}$ and $\mathrm{I}$, then respectively equal to :
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Verified Answer
The correct answer is:
$-\mathrm{r}$ and $\in$
$$
\begin{aligned}
& \quad \mathrm{E}=\mathrm{V}+\mathrm{Ir} \\
& \Rightarrow \mathrm{V}=\mathrm{E}-\mathrm{Ir} \\
& \text { Comparing with } \mathrm{y}=\mathrm{mx}+\mathrm{c} \\
& \text { Slope }=-\mathrm{r} \text {, intercept }=\mathrm{E}
\end{aligned}
$$
\begin{aligned}
& \quad \mathrm{E}=\mathrm{V}+\mathrm{Ir} \\
& \Rightarrow \mathrm{V}=\mathrm{E}-\mathrm{Ir} \\
& \text { Comparing with } \mathrm{y}=\mathrm{mx}+\mathrm{c} \\
& \text { Slope }=-\mathrm{r} \text {, intercept }=\mathrm{E}
\end{aligned}
$$
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