A student measures the time period of 100 oscillations of a simple pendulum four times. The data set is 90 s, 91 s, 95 s and 92 s. If the minimum division in the measuring clock is 1 s, then the reported mean time should be:

Question

A student measures the time period of 100 oscillations of a simple pendulum four times. The data set is 90 s, 91 s, 95 s and 92 s. If the minimum division in the measuring clock is 1 s, then the reported mean time should be:, 92 ± 1.8 s, 92 ± 3 s, 92 ± 2 s, 92 ± 5.0 s

MARKS App · Accepted Answer

T T s T i - T t 1 90 - 2 t 2 91 - 1 t 3 95 3 t 4 92 0 T i 92 Σ |T i - T| N = 1.5 T r = 9 2 ± 1.5 T r = 9 2 ± 2 Because least count of clock is 1s

T	$T_{s}$	$T_{i} - T$
$t_{1}$	90	- 2
$t_{2}$	91	- 1
$t_{3}$	95	3
$t_{4}$	92	0
$T_{i}$	92	$\frac{Σ {\|T}_{i} - T\|}{N} = 1.5$

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