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Question: Answered & Verified by Expert
A substance 'A' decomposes by a first order reaction starting initially with \([\mathrm{A}]=2.00 \mathrm{~m}\) and after \(200 \mathrm{~min},[\mathrm{~A}]\) becomes \(0.15 \mathrm{~m}\). For this reaction \(t_{1 / 2}\) is
ChemistryChemical KineticsVITEEEVITEEE 2022
Options:
  • A \(53.72 \mathrm{~min}\)
  • B \(50.49 \mathrm{~min}\)
  • C \(48.45 \mathrm{~min}\)
  • D \(46.45 \mathrm{~min}\)
Solution:
1735 Upvotes Verified Answer
The correct answer is: \(53.72 \mathrm{~min}\)
Given initial concentration (a) \(=2.00 \mathrm{~m}\); Time taken \((t)=200 \mathrm{~min}\) and final concentration \((\mathrm{a}-\mathrm{x})=0.15 \mathrm{~m}\). For a first order reation rate constant,

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