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A system is provided with $50 \mathrm{~J}$ of heat and the work done on the system is $10 \mathrm{~J}$. What is the change in internal energy of the system in joules?
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2485 Upvotes
Verified Answer
The correct answer is:
60
From first law of thermodynamics,
$\Delta E=Q+W$
Since, heat is provided to the system,
$Q=+50 \mathrm{~J}$
and work is done on the system,
$W =+10 \mathrm{~J}$
$\therefore \Delta E =50+10=60 \mathrm{~J}$
$\Delta E=Q+W$
Since, heat is provided to the system,
$Q=+50 \mathrm{~J}$
and work is done on the system,
$W =+10 \mathrm{~J}$
$\therefore \Delta E =50+10=60 \mathrm{~J}$
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