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A tall tank filled with water has an irregular shape as shown. The wall $\mathrm{CD}$ makes an angle of $45^{\circ}$ with the horizontal; the wall $\mathrm{AB}$ is normal to the base $\mathrm{BC}$. The lengths $\mathrm{AB}$ and $\mathrm{CD}$ are much smaller than the height h of water (figure not to scale).
Let $\mathrm{P}_{1}, \mathrm{P}_{2}$ and $\mathrm{P}_{3}$ be the pressures exerted by the water on the wall $\mathrm{AB}$, base $\mathrm{BC}$ and the wall $\mathrm{CD}$ respectively. Density of water is $\rho$ and $g$ is acceleration due to gravity. Then, approximately
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Let $\mathrm{P}_{1}, \mathrm{P}_{2}$ and $\mathrm{P}_{3}$ be the pressures exerted by the water on the wall $\mathrm{AB}$, base $\mathrm{BC}$ and the wall $\mathrm{CD}$ respectively. Density of water is $\rho$ and $g$ is acceleration due to gravity. Then, approximately
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Verified Answer
The correct answer is:
$P_{1}=P_{2}=P_{3}$
All are nearly at same height hence $\mathrm{P}_{1}=\mathrm{P}_{2}=\mathrm{P}_{3}$
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