Search any question & find its solution
Question:
Answered & Verified by Expert
A tangent galvanometer has a reduction factor of $1 \mathrm{~A}$ and it is placed with the plane of its coil perpendicular to the magnetic meridian. The deflection produced when a current of $I A$ is passed through it is
Options:
Solution:
2124 Upvotes
Verified Answer
The correct answer is:
$45^{\circ}$
The deflection in a tangent galvanometer is given by
$\tan \theta=\frac{I}{K}$
where, $K=$ reduction factor
Here, $K=1 \mathrm{~A}, I=1 \mathrm{~A}$
$\therefore \quad \tan \theta=\frac{1}{1}=1 \Rightarrow \theta=45^{\circ}$
$\tan \theta=\frac{I}{K}$
where, $K=$ reduction factor
Here, $K=1 \mathrm{~A}, I=1 \mathrm{~A}$
$\therefore \quad \tan \theta=\frac{1}{1}=1 \Rightarrow \theta=45^{\circ}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.