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A tank with vertical walls is mounted so that its base is at a height $H$ above the horizontal ground. The tank is filled with water to a depth $h$. A hole is punched in the side wall of the tank at a depth $x$ below the water surface. To have maximum range of the emerging stream, the value of $x$ is
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The correct answer is:
$\frac{H+h}{2}$
Total height of water level from the ground $=(h+H)$
From Torrcelli's theorem we know that to have maximum range, the depth of hole. $x=\frac{(h+H)}{2}$
From Torrcelli's theorem we know that to have maximum range, the depth of hole. $x=\frac{(h+H)}{2}$
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