A thin circular ring of mass M and radius r is rotating about its axis with an angular speed ω . Two particles having mass m each are now attached at diametrically opposite points. The angular speed of the ring will become:

Question

A thin circular ring of mass M and radius r is rotating about its axis with an angular speed ω . Two particles having mass m each are now attached at diametrically opposite points. The angular speed of the ring will become:, ω M M + m, ω M + 2 m M, ω M M + 2 m, ω M - 2 m M + 2 m

MARKS App · Accepted Answer

Using conservation of angular momentum ⇒ M r 2 ω = M r 2 + 2 m r 2 ω ' ⇒ ω ' = M ω M + 2 m .

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