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Question: Answered & Verified by Expert
A thin lens has a focal length f and its aperture has a diameter d. It forms an image of intensity I. Now the central part of the aperture up to diameter d2 is blocked by an opaque paper. The focal length and image intensity would change to
PhysicsRay OpticsNEET
Options:
  • A f2I2
  • B fI4
  • C 3f4I2
  • D f3I4
Solution:
1764 Upvotes Verified Answer
The correct answer is: f3I4
The focal length remains f, as any small portion of the lens forms a complete image of the object and has the same focal length.

While the intensity of the image depends on the area as,

IntensityArea2

I2I1=A2A1

I2I=πd24-πd224πd24

I2I=34

I2=34I

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