Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A thin plastic sheet of refractive index 1.6 is used to cover one of the slits, among the two slits, in a double-slit arrangement. The central point on the screen is now occupied by what would have been the 7th bright fringe before the thin plastic sheet was used. If the wavelength of light is 600 nm, the thickness (in μm) of the thin plastic sheet is
PhysicsWave OpticsJEE Main
Options:
  • A 7
  • B 4
  • C 8
  • D 6
Solution:
2018 Upvotes Verified Answer
The correct answer is: 7
The change in path =μ-1t. This path length change the position of bright fringe upto seventh bright fringe. 

t( μ1 )=7λ

t= 7( 600× 10 9 ) ( 1.61 )

=7×106 m     7 μm

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.