Search any question & find its solution
Question:
Answered & Verified by Expert
A thin ring of radius $R$ metre has charge $q$ coulomb uniformly spread on it. The ring rotates about its axis with a constant frequency of $f$ revolution/s. The value of magnetic induction in $\mathrm{Wb} \mathrm{m}^{-2}$ at the centre of the ring is
Options:
Solution:
2983 Upvotes
Verified Answer
The correct answer is:
$\frac{\mu_0 q f}{2 R}$
The magnetic field at the centre of the circle
\(B=\frac{\mu_0 I}{2 R}=\frac{\mu_0}{2 R}\left(\frac{q}{t}\right)=\frac{\mu_0 q f}{2 R}\)
\(B=\frac{\mu_0 I}{2 R}=\frac{\mu_0}{2 R}\left(\frac{q}{t}\right)=\frac{\mu_0 q f}{2 R}\)
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.