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A thin rod of length $L$ and mass $M$ is bent at its midpoint into two halves so that the angle between them is $90^{\circ}$. The moment of inertia of the bent rod about an axis passing through the bending point and perpendicular to the plane defined by the two halves of the rod is
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The correct answer is:
$\frac{M L^2}{12}$
Distribution of masses about axis of rotation remain unchanged whether it is straight or bend.
$$
I=\frac{M L^2}{12}
$$
$$
I=\frac{M L^2}{12}
$$
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