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A thin sheet of glass $(\mu=1.5)$ of thickness 6 micron introduced in the path of one of the interfering beams in a double slit experiment shifts the central fringe to a position previously occupied by fifth bright fringe. Then the wavelength of light used is
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$6000 Ã$
$\mathrm{n} \lambda=(\mu-1) \mathrm{t} ;$
$\therefore \lambda=\frac{(\mu-1) \mathrm{t}}{\mathrm{n}}=\frac{(1.5-1) \times 6 \times 10^{-6}}{5}=6000 \mathrm{~A}$
$\therefore \lambda=\frac{(\mu-1) \mathrm{t}}{\mathrm{n}}=\frac{(1.5-1) \times 6 \times 10^{-6}}{5}=6000 \mathrm{~A}$
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