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A thin spherical shell is charged by some source. The potential difference between the two points $C$ and $P$ (in V ) shown in the figure is:
(Take $\frac{1}{4 \pi \varepsilon_0}=9 \times 10^9$ SI units)
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(Take $\frac{1}{4 \pi \varepsilon_0}=9 \times 10^9$ SI units)
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1996 Upvotes
Verified Answer
The correct answer is:
Zero
For uniformly charged spherical shell,
$\begin{aligned}
& V=\frac{k q}{R} \quad(\text { For } r \leq R) \\
& \therefore \quad V_C=V_P \\
& \\
& V_C-V_P=\text { Zero }
\end{aligned}$
$\begin{aligned}
& V=\frac{k q}{R} \quad(\text { For } r \leq R) \\
& \therefore \quad V_C=V_P \\
& \\
& V_C-V_P=\text { Zero }
\end{aligned}$
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