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A thin tube sealed at both ends is $100 \mathrm{~cm}$ long. It lies horizontally, the middle $20 \mathrm{~cm}$ containing mercury and two equal ends containing air at standard atmospheric pressure. If the tube is now turned to a vertical position, by what amount will the mercury be displaced ?

(Given : cross-section of the tube can be assumed to be uniform)
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(Given : cross-section of the tube can be assumed to be uniform)
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The correct answer is:
$5.18 \mathrm{~cm}$
$5.18 \mathrm{~cm}$
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