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A thin uniform rod of length 'L' and mass 'M' is bent at the middle point ' 0 ' at an angle
of $45^{\circ}$ as shown in the figure. The moment of inertia of the system about an axis
passing through '0' and perpendicular to the plane of the bent rod, is
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of $45^{\circ}$ as shown in the figure. The moment of inertia of the system about an axis
passing through '0' and perpendicular to the plane of the bent rod, is
Solution:
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Verified Answer
The correct answer is:
$\frac{\mathrm{ML}^{2}}{12}$
Moment of inertia of each half of the rod about the mid point is given by
$I_{1}=\frac{\frac{M}{2}\left(\frac{L}{2}\right)^{2}}{3}=\frac{M L^{2}}{24}$
Total moment of inertia $=\mathrm{I}=2 \mathrm{I}_{1}=\frac{\mathrm{ML}^{2}}{12}$
$I_{1}=\frac{\frac{M}{2}\left(\frac{L}{2}\right)^{2}}{3}=\frac{M L^{2}}{24}$
Total moment of inertia $=\mathrm{I}=2 \mathrm{I}_{1}=\frac{\mathrm{ML}^{2}}{12}$
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