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A thin wire of length ' $L$ ' made of an insulating material is bent to form a circular loop and a positive charge ' $\mathrm{q}$ ' is given so that it is distributed uniformly around the circumference of the loop. The loop is then rotated with an angular speed ' $\omega$ ' about an axis passing through its centre. If a uniform magnetic field B directed parallel to the plane of the loop is applied then the magnitude of the magnetic torque on the loop is
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The correct answer is:
$\frac{\mathrm{q} \omega \mathrm{L}^2 \mathrm{~B}}{8 \pi^2}$
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