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A toroidal solenoid with air core has an average radius ' $\mathrm{R}^{\prime}$, number of turns ' $\mathrm{N}^{\prime}$ and
area of cross-section 'A'. The self-inductance of the solenoid is (Neglect the field variation across the cross-section of the toroid)
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area of cross-section 'A'. The self-inductance of the solenoid is (Neglect the field variation across the cross-section of the toroid)
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Verified Answer
The correct answer is:
$\frac{\mu_{0} \mathrm{~N}^{2} \mathrm{~A}}{2 \pi \mathrm{R}}$
Theory question.
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