A tower P Q stands on a horizontal ground with base Q on the ground. The point R divides the tower in two parts such that Q R = 15 m . If from a point A on the ground the angle of elevation of R is 60 ° and the part P R of the tower subtends an angle of 15 ° at A , then the height of the tower is

Question

A tower P Q stands on a horizontal ground with base Q on the ground. The point R divides the tower in two parts such that Q R = 15 m . If from a point A on the ground the angle of elevation of R is 60 ° and the part P R of the tower subtends an angle of 15 ° at A , then the height of the tower is, 5 2 3 + 3 m, 5 3 + 3 m, 10 3 + 1 m, 10 2 3 + 1 m

MARKS App · Accepted Answer

Plotting the diagram of the given values we get, From the right triangle R Q S , tan 60 ° = 15 a a = 15 3 = 5 3 In right triangle P Q S , tan 75 ° = h a ⇒ h 5 3 = 2 + 3 ⇒ h = 10 3 + 15 ⇒ h = 5 2 3 + 3

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