A toy car with charge q moves on a frictionless horizontal plane surface under the influence of a uniform electric field E → . Due to the force q E → , its velocity increases from 0 to 6 m s - 1 in one second duration. At that instant the direction of the field is reversed. The car continues to move for two more seconds under the influence of this field. The average velocity and the average speed of the toy car between 0 to 3 seconds are respectively

Question

A toy car with charge q moves on a frictionless horizontal plane surface under the influence of a uniform electric field E → . Due to the force q E → , its velocity increases from 0 to 6 m s - 1 in one second duration. At that instant the direction of the field is reversed. The car continues to move for two more seconds under the influence of this field. The average velocity and the average speed of the toy car between 0 to 3 seconds are respectively, 1 m s - 1 , 3.5 m s - 1, 1 m s - 1 , 3 m s - 1, 2 m s - 1 , 4 m s - 1, 1.5 m s - 1 , 3 m s - 1

MARKS App · Accepted Answer

0 t ≤ 1 s velocity increases from 0 to 6 m/s 1 s ≤ t ≤ 2 s : velocity decreases from 6 m/s to 0 m/s But car continues to move forward and then it reverses its direction at t = 2 s and after 2 s accelerates backward Distance undefined | 1 2 × 6 × 2 | + | 1 2 × ( − 6 ) × 1 | = 6 + 3 = 9 m Displacement = Total area under v − t graph = 6 − 3 = 3 m ∴ Average velocity = Displacement Time = 3 3 = 1 m/s ∴ Average speed = Total distance Time = 9 3 = 3 m/s

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