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A transformer has 20 turns in the primary and 100 turns in the secondary coil. An ac voltage of $\mathrm{V}_{\text {in }}=600 \sin 314 \mathrm{t}$ is applied to primary terminal of transformer. Then maximum value of secondary output voltage obtained in volt is
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Verified Answer
The correct answer is:
3000
We know,
$$
\frac{V_s}{V_p}=\frac{N_s}{N_p}
$$
$\therefore \quad$ The maximum value of secondary output voltage is:
$$
\begin{aligned}
V_s & =\frac{N_s}{N_p} \times V_p=\frac{100}{20} \times 600 \\
V_s & =3000 V
\end{aligned}
$$
$$
\frac{V_s}{V_p}=\frac{N_s}{N_p}
$$
$\therefore \quad$ The maximum value of secondary output voltage is:
$$
\begin{aligned}
V_s & =\frac{N_s}{N_p} \times V_p=\frac{100}{20} \times 600 \\
V_s & =3000 V
\end{aligned}
$$
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