A transformer operating at primary voltage 8 kV and secondary voltage 160 V serves a load of 80 kW . Assuming the transformer to be ideal with purely resistive load and working on unity power factor, the loads in the primary and secondary circuit would be

Question

A transformer operating at primary voltage 8 kV and secondary voltage 160 V serves a load of 80 kW . Assuming the transformer to be ideal with purely resistive load and working on unity power factor, the loads in the primary and secondary circuit would be, 800 Ω and 1 . 06 Ω, 10 Ω and 500 Ω, 800 Ω and 0 . 32 Ω, 1 . 06 Ω and 500 Ω

MARKS App · Accepted Answer

Since the transformer is assumed to be purely resistive, the power of the transformer can be calculated with P = V 2 R . Therefore, For the primary coil, P = 8 × 10 3 2 R P = 80 × 10 3 W ⇒ R P = 800 Ω For the secondary coil, P = 160 2 R S = 80 × 10 3 W ⇒ R S = 0 . 32 Ω

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