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A transformer rated at $10 \mathrm{~kW}$ is used to connect a $5 \mathrm{kV}$ transmission line to a $240 \mathrm{~V}$ circuit. The ratio of turns in the windings of the transformer is
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The correct answer is:
$20.8$
In a transformer, the ratio of turns in the windings is given by
$\begin{aligned}
& \frac{\mathrm{N}_{\mathrm{P}}}{\mathrm{N}_{\mathrm{S}}}=\frac{\mathrm{V}_{\mathrm{P}}}{\mathrm{V}_{\mathrm{S}}} \\
\therefore & \frac{\mathrm{N}_{\mathrm{P}}}{\mathrm{N}_{\mathrm{S}}}=\frac{5 \mathrm{kV}}{240 \mathrm{~V}}=\frac{5000 \mathrm{~V}}{240 \mathrm{~V}}=20.8
\end{aligned}$
$\begin{aligned}
& \frac{\mathrm{N}_{\mathrm{P}}}{\mathrm{N}_{\mathrm{S}}}=\frac{\mathrm{V}_{\mathrm{P}}}{\mathrm{V}_{\mathrm{S}}} \\
\therefore & \frac{\mathrm{N}_{\mathrm{P}}}{\mathrm{N}_{\mathrm{S}}}=\frac{5 \mathrm{kV}}{240 \mathrm{~V}}=\frac{5000 \mathrm{~V}}{240 \mathrm{~V}}=20.8
\end{aligned}$
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