Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A transistor is connected in common emitter circuit configuration, the collector supply voltage is 10 V and the voltage drop across a resistor of 1000 Ω in the collector circuit is 0.6 V. If the current gain factor (β) is 24, then the base current is ____μA. (Round off to the Nearest Integer)
PhysicsSemiconductorsJEE MainJEE Main 2021 (27 Jul Shift 1)
Solution:
1877 Upvotes Verified Answer
The correct answer is: 25

β=ICIB=24;  RC=1000

ΔV=0.6

IC=0.61000

IC=6×10-4
IB=ICβ=6×10-424=25 μA

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.