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Question: Answered & Verified by Expert
A transverse wave is described by the equation $y=y_0 \sin 2 \pi\left(v t-\frac{x}{\lambda}\right)$. The maximum particle velocity is equal to four times the wave velocity if $\lambda=$
PhysicsWaves and SoundAP EAMCETAP EAMCET 2017 (25 Apr Shift 1)
Options:
  • A $\lambda=\frac{\pi \mathrm{y}_0}{4}$
  • B $\lambda=\frac{\pi \mathrm{y}_0}{2}$
  • C $\lambda=2 \pi \mathrm{y}_0$
  • D $\lambda=\frac{\pi}{\mathrm{y}_0}$
Solution:
2415 Upvotes Verified Answer
The correct answer is: $\lambda=2 \pi \mathrm{y}_0$
No solution. Refer to answer key.

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