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A transverse wave is represented by the equation $y=2 \sin (30 t-40 x)$ and the measurements of distances are in meters, then the velocity of propagation is
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The correct answer is:
$0.75\ ms{-1}$
We have $y=2 \sin (30 t-40 x)$
The standard transverse wave is $y=A \sin (\omega t-k x)$
So, $\omega=30$ and $k=40$
On comparing, we get
$v=\frac{\omega}{k}=\frac{30}{40}=0.75 \mathrm{~m} / \mathrm{s}$
The standard transverse wave is $y=A \sin (\omega t-k x)$
So, $\omega=30$ and $k=40$
On comparing, we get
$v=\frac{\omega}{k}=\frac{30}{40}=0.75 \mathrm{~m} / \mathrm{s}$
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