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A tuned amplifier circuit is used to generate a carrier frequency of \( 2 \mathrm{MHz} \) for the amplitude
modulation. The value of \( \sqrt{\mathrm{LC}} \) is
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modulation. The value of \( \sqrt{\mathrm{LC}} \) is
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Verified Answer
The correct answer is:
\( \frac{1}{4 \Pi \times 10^{6}} \)
We know \( f=\frac{1}{2 \pi \sqrt{L} C} \)
\( \Rightarrow \sqrt{L} C=\frac{1}{2 \pi f} \)
Given \( f=2 \mathrm{MHz}=2 \times 10^{6} \mathrm{~Hz} \)
Therefore, \( \sqrt{L C}=\frac{1}{2 \Pi \times 2 \times 10^{6}}=\frac{1}{4 \Pi \times 10^{6}} \)
\( \Rightarrow \sqrt{L} C=\frac{1}{2 \pi f} \)
Given \( f=2 \mathrm{MHz}=2 \times 10^{6} \mathrm{~Hz} \)
Therefore, \( \sqrt{L C}=\frac{1}{2 \Pi \times 2 \times 10^{6}}=\frac{1}{4 \Pi \times 10^{6}} \)
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