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A tuning fork arrangement (pair) produces 4 beats / sec with one fork of frequency $288 \mathrm{cps}$. A little wax is placed on the unknown fork and it then produces 2 beats /sec. The frequency of the unknown fork is
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The correct answer is:
292 cps
292 cps
The fact that placing wax decreases the frequency of the unknown fork and also the beat frequency states that the unknown fork is of higher frequency.
$$
n-288=4 \Rightarrow n=292 \mathrm{cps}
$$
$$
n-288=4 \Rightarrow n=292 \mathrm{cps}
$$
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