Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A tuning fork of frequency 100 Hz when sounded together with another tuning fork of unknown frequency produces 2 beats per second. On loading the tuning fork whose frequency is not known and sounded together with a tuning fork of frequency 100 Hz produces one beat, then the frequency of the other tuning fork is
PhysicsWaves and SoundNEET
Options:
  • A 102
  • B 98
  • C 99
  • D 101
Solution:
1374 Upvotes Verified Answer
The correct answer is: 102
Suppose nA is known frequency, then nA=100 Hz, and let nB be the frequency of the other tuning fork

x=2=Beat frequency, which is decreasing after loading (i.e. x)

Unknown tuning fork is loaded so nB decreases and also given that beat frequency is 1, so beat frequency also decreases

Hence, nB>nA and nB-nA =x

nB=nA+x=100+2=102 Hz

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.