A uniform circular loop of radius a and resistance R is pulled at a constant velocity v out of a region of a uniform magnetic field whose magnitude is B . The plane of the loop and the velocity are both perpendicular to B . Then the electrical power in the circular loop at the instant when the arc (of the circular loop) outside the region of magnetic field subtends an angle π 3 at the centre of the loop is

Question

A uniform circular loop of radius a and resistance R is pulled at a constant velocity v out of a region of a uniform magnetic field whose magnitude is B . The plane of the loop and the velocity are both perpendicular to B . Then the electrical power in the circular loop at the instant when the arc (of the circular loop) outside the region of magnetic field subtends an angle π 3 at the centre of the loop is, B 2 a 2 v 2 R, 2 B 2 a 2 v 2 R, B 2 a 2 v 2 2 R, none of these

MARKS App · Accepted Answer

The induced emf in the circular loop = B PQ v = Bav Therefore electrical power consumed by the circular loop = emf 2 R = Bav 2 R

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