A uniform current carrying ring of mass m and radius R is connected by a massless string as shown in diagram. A uniform magnetic field B 0 exists in the region to keep the ring in horizontal position, then the current in the ring is ( l ⁡ length of string)

Question

A uniform current carrying ring of mass m and radius R is connected by a massless string as shown in diagram. A uniform magnetic field B 0 exists in the region to keep the ring in horizontal position, then the current in the ring is ( l ⁡ length of string), mg π RB 0, mg RB 0, mg 3 π RB 0, mg ℓ π R 2 B 0

MARKS App · Accepted Answer

Torque due to magnetic field τ mag = MB 0 = I π R 2 B 0 ...(i) Torque due to weight about the point where string is connected τ weight = mgR ...(ii) If ring remains horizontal, then τ mag = τ weight I π R 2 B 0 = mgR ⇒ I = mg π RB 0

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