A uniform electric field E = 8 m e V m - 1 is created between two parallel plates of length 1 m as shown in figure, (where m = mass of electron and e = charge of electron). An electron enters the field symmetrically between the plates with a speed of 2 m s - 1 . The angle of the deviation θ of the path of the electron as it comes out of the field will be _____ .

Question

A uniform electric field E = 8 m e V m - 1 is created between two parallel plates of length 1 m as shown in figure, (where m = mass of electron and e = charge of electron). An electron enters the field symmetrically between the plates with a speed of 2 m s - 1 . The angle of the deviation θ of the path of the electron as it comes out of the field will be _____ ., tan - 1 4, tan - 1 2, tan - 1 1 3, tan - 1 3

MARKS App · Accepted Answer

Time taken by the electron to cross will be, t = 1 v x = 1 2 s . Acceleration of the electron along y axis a g = F m = E e m = 8 m e × e m = 8 m s - 2 v y of the electron when it has crossed the capacitor will be, v y = a y t = 8 × 1 2 = 4 m s - 1 Therefore, tan θ = v y v x = 4 2 = 2 ⇒ θ = tan - 1 2

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