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Question: Answered & Verified by Expert
A uniform metal wire of length 'L', mass ' M' and density ' 0 ' is under a tension ' $\mathrm{T}^{\prime}$ '. If the speed of transverse wave along the wire is ' $V^{\prime}$, then area of cross-section of the wire is
PhysicsWaves and SoundMHT CETMHT CET 2020 (15 Oct Shift 2)
Options:
  • A $\frac{\mathrm{V}}{\mathrm{Te}}$
  • B $\frac{\mathrm{T}}{\mathrm{V}^{2}} \mathrm{Q}$
  • C $\frac{\mathrm{T}^{2}}{\mathrm{~V}_{\mathrm{Q}}}$
  • D $\frac{\mathrm{V}^{2}}{\mathrm{~T} \mathrm{e}}$
Solution:
1859 Upvotes Verified Answer
The correct answer is: $\frac{\mathrm{T}}{\mathrm{V}^{2}} \mathrm{Q}$
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