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A uniform rod $A B$ of length ' $L$ ' and mass ' $M$ ' is pivoted at the centre ' $O$ ' in such a way that it can rotate in the vertical plane as shown in the figure. An insect of the same mass falls vertically with speed ' $\mathrm{v}$ ' on the horizontal rod at a point ' $\mathrm{C}$ ' which is the midpoint of $\mathrm{O}$ and $\mathrm{B}$. Immediately after falling, the insect moves towards the end $B$ such that the rod rotates with constant angular velocity ' $\omega$ '. If the insect reaches the end B when the rod has turned through $90^{\circ}$, then the speed $v$ is

PhysicsRotational MotionAP EAMCETAP EAMCET 2018 (24 Apr Shift 2)
Options:
  • A $\frac{12}{7} \mathrm{gL}$
  • B $\frac{7}{12} \sqrt{2 \mathrm{gL}}$
  • C $\frac{7}{12} \sqrt{ \mathrm{gL}}$
  • D $\frac{12}{7} \sqrt{ \mathrm{gL}}$
Solution:
1131 Upvotes Verified Answer
The correct answer is: $\frac{7}{12} \sqrt{2 \mathrm{gL}}$
No solution. Refer to answer key.

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