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Question: Answered & Verified by Expert
A uniform rod PQ of length l and mass m is placed on a smooth horizontal surface. It is hinged at one of its ends and touches the conducting circular loop at another end. The system is subjected to vertical magnetic field B0. Rod is given angular velocity ω0 about the axis passing through P. If the time after which its angular velocity becomes half is abmRln2B2l2 . Find the value of a+b, where a and b are smallest positive integers.
 
PhysicsElectromagnetic InductionJEE Main
Solution:
2498 Upvotes Verified Answer
The correct answer is: 7
ε=12B0ωl2
I=12B0ωl2R
τ=Il2B04=14B0ωl2Rl2B0
B02ωl4R=ml23dωdt
3B2l24mRt=-dωdt
t=4mRln23B2l2
a=4and b=3 a+b=4+3=7

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