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Question: Answered & Verified by Expert
A uniform rope of mass 6 kg and length 6 m hangs vertically from a rigid support. A block of mass 2 kg is attached to the free end of the rope. A transverse pulse of wavelength 0.075 m is produced at the lower end of the rope. The wavelength of the pulse when it reaches the top of the rope is K cm where K is
PhysicsWaves and SoundJEE Main
Solution:
1717 Upvotes Verified Answer
The correct answer is: 15
T1= 2 × 10 = 20 N
T2 = (2 + 6) 10 = 80 N
V2V1=8020=2
Frequency remains unchanged
So λ2λ1=2
λ2=2×0.075
= 0.15 m
K=15 cm

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