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A uniform wire of length $l$ and having resistance $R$ is cut into $n$ equal parts and all parts are connected in parallel, then the equivalent resistance will be :
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Verified Answer
The correct answer is:
$R / n^2$
Resistance of each part $R^{\prime}=\frac{R}{n}$
When, these parts are connected in parallel.
Then, $\frac{1}{R^{\prime \prime}}=\frac{1}{R^{\prime}}+\frac{1}{R^{\prime}} \ldots . n$ time
$\begin{aligned} & =\frac{n}{R^{\prime}} \\ \therefore \quad R^{\prime \prime} & =\frac{R^{\prime}}{n}=\frac{R}{n^2}\end{aligned}$
When, these parts are connected in parallel.
Then, $\frac{1}{R^{\prime \prime}}=\frac{1}{R^{\prime}}+\frac{1}{R^{\prime}} \ldots . n$ time
$\begin{aligned} & =\frac{n}{R^{\prime}} \\ \therefore \quad R^{\prime \prime} & =\frac{R^{\prime}}{n}=\frac{R}{n^2}\end{aligned}$
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