A vertical electric field of magnitude 4 . 9 × 10 5 N C - 1 just prevents a water droplet of a mass 0 . 1 g from falling. The value of charge on the droplet will be : (Given g = 9 . 8 m s - 2 )

Question

A vertical electric field of magnitude 4 . 9 × 10 5 N C - 1 just prevents a water droplet of a mass 0 . 1 g from falling. The value of charge on the droplet will be : (Given g = 9 . 8 m s - 2 ), 1 . 6 × 10 - 9 C, 2 . 0 × 10 - 9 C, 3 . 2 × 10 - 9 C, 0 . 5 × 10 - 9 C

MARKS App · Accepted Answer

To balance gravitational force, electric force on the liquid drop should act in upward direction. For translational equilibrium along vertical direction, q E = m g ⇒ q = m g E = 0 . 1 × 10 - 3 × 9 . 8 4 . 9 × 10 5 = 2 . 0 × 10 - 9 C

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