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Question: Answered & Verified by Expert

A vertical spring of force constant 100 Nm-1 is attached to the ceiling, with a block of mass 10 kg suspended from it. Now an external force F is applied on the block so that the spring is stretched by an additional length of 2 m. The work done by the force F is [Take g=10 ms-2]


PhysicsWork Power EnergyJEE Main
Options:
  • A 200 J
  • B 400 J
  • C 100 J
  • D 600 J
Solution:
2629 Upvotes Verified Answer
The correct answer is: 200 J
x = elongation in spring due to mass 10 kg

= 1 0 × 1 0 1 0 0 = 1 m

W F = 1 2 × 1 0 0 × 3 2 - 1 2 - 1 0 × 1 0 × 2

= 200 J

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