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Question: Answered & Verified by Expert
A vessel ABCD of 10 cm width has two small slits S 1 and S 2  sealed with identical glass plates of equal thickness. The distance between the slits is 0.8 mm . POQ is the line perpendicular to the plane AB and passing through O , the



middle point of S 1 and S 2, A monochromatic light source  is kept at S, 40 cm cm below P and 2 m from the vessel, to illuminate the slits as shown in the figure alongside. After a liquid is poured into the vessel and filled upto OQ, it was found that the central bright fringe is now located at Q. Calculate the refractive index of that liquid.
PhysicsWave OpticsJEE Main
Options:
  • A 1.0016
  • B 2.0032
  • C 1.0010
  • D 1.0026
Solution:
2362 Upvotes Verified Answer
The correct answer is: 1.0016
 Given Y 1 =40  cm, D 1 =2m=200cm, D 2 =10cm

  tan α = y 1 D 1 = 4 0 2 0 0 = 1 5

   ∴  α = tan -1 1 / 5

  sin α = 1 2 6 1 5 = tan α



Initial path difference Δx 1 ,=  SS 1 SS 2 = y 1 d D 1  = y 1 d D 1 & geometrical path difference Δ x 2 S 1 R S 2 R= - y 2 d D 2

For central maxima, total path difference has to be zero.

i.e., y 1 d D 1 - y 2 d D 2 = 0

y 2 = y 1 D 2 D 1 = 4 0 cm × 1 0 cm 2 0 0 cm = 2 cm

Now as central bright fringe is at Q. them the optical path difference is μ - 1 t & for central maxima μ - 1 t = Δ x 1

μ = 1 + Δ x 1 t = 1 + y 1 d t D 1

= 1 + 0 . 4 m × 0 . 8 mm 0 . 1 m × 2 m

= 1 + 2 × 0 . 8 × 1 0 - 3

= 1 + 1 . 6 × 1 0 - 3

= 1 . 0 0 1 6

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